jQuery技术:jsTree – 不要选择父节点的禁用子节点？

我的解决方案在1-deep树上进行了测试。 我刚刚添加了这个function：

 //select parents children except disabled ones //test on 1-deep $("#selectionTree").on("select_node.jstree", function(evt, data) { var currentNode = data.node; //rember opened state for later var openedState = currentNode['state']['opened']; //need to open node for accruate selection $('#selectionTree').jstree('open_node', currentNode); //get child nodes var children = $(this).jstree("get_children_dom", currentNode); //this allows selections parent nodes to deselect children (without it, there is no three-state) if ($("#" + currentNode['a_attr']['id'] + " > i").hasClass("jstree-undetermined")) { for (var i = 0; i < children.length; i++) { $(children[i]).jstree("deselect_node", children[i]); } } //loop through child nodes and select all except disabled nodes for (var i = 0; i < children.length; i++) { var obj = $.parseJSON($(children[i]).attr('data-jstree')); if (obj['disabled'] == true) { $(children[i]).jstree("deselect_node", children[i]); } } //return parent to closed state if was already if (openedState == false) { $(this).jstree('close_node', currentNode); } }); 

工作小提琴： https ： //jsfiddle.net/Lf55r7qt/6/