为目标数组分配空间，使用Array.CopyTo（）：

 targetArray = new string[sourceArray.Length]; sourceArray.CopyTo( targetArray, 0 ); 

例如：

 using System; class Test { static void Main(string[] args) { // Clone the whole array string[] args2 = (string[]) args.Clone(); // Copy the five elements with indexes 2-6 // from args into args3, stating from // index 2 of args3. string[] args3 = new string[5]; Array.Copy(args, 2, args3, 0, 5); // Copy whole of args into args4, starting from // index 2 (of args4) string[] args4 = new string[args.Length+2]; args.CopyTo(args4, 2); } } 

假设我们从args = { "a", "b", "c", "d", "e", "f", "g", "h" } ，结果如下：

 args2 = { "a", "b", "c", "d", "e", "f", "g", "h" } args3 = { "c", "d", "e", "f", "g" } args4 = { null, null, "a", "b", "c", "d", "e", "f", "g", "h" } 

以上答案显示浅层克隆; 所以我想我使用序列化添加了一个深层克隆示例; 当然，深度克隆也可以通过循环原始数组并将每个元素复制到一个全新的数组中来完成。

  private static T[] ArrayDeepCopy(T[] source) { using (var ms = new MemoryStream()) { var bf = new BinaryFormatter{Context = new StreamingContext(StreamingContextStates.Clone)}; bf.Serialize(ms, source); ms.Position = 0; return (T[]) bf.Deserialize(ms); } } 

测试深度克隆：

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  private static void ArrayDeepCloneTest() { //a testing array CultureInfo[] secTestArray = { new CultureInfo("en-US", false), new CultureInfo("fr-FR") }; //deep clone var secCloneArray = ArrayDeepCopy(secTestArray); //print out the cloned array Array.ForEach(secCloneArray, x => Console.WriteLine(x.DateTimeFormat.DateSeparator)); //modify the original array secTestArray[0].DateTimeFormat.DateSeparator = "-"; Console.WriteLine(); //show the (deep) cloned array unchanged whereas a shallow clone would reflect the change... Array.ForEach(secCloneArray, x => Console.WriteLine(x.DateTimeFormat.DateSeparator)); }