在WinForm项目选项卡中运行exe

我对使用winform应用程序执行以下操作感兴趣，我正在编写，以在Visual Studio 2010 IDE中的c＃中的.exe中打开。

我现在可以通过使用以下代码在所需选项卡中单击按钮来打开程序：

string str = @"-INSERT FILEPATH HERE-";//took file path out as i have a few exes i'm wanting to add. Process process = new Process(); process.StartInfo.FileName = str; process.Start(); 

现在我怎么能这样做，所以这个可执行文件作为选项卡打开或在选项卡中，在我的winform中？ 我愿意接受任何一种情况的建议。

解决了：

 using System.Runtime.InteropServices; using System.Threading; [DllImport("user32.dll", SetLastError = true)] private static extern bool MoveWindow(IntPtr hwnd, int x, int y, int cx, int cy, bool repaint); [DllImport("user32.dll", SetLastError = true)] static extern IntPtr SetParent(IntPtr hWndChild, IntPtr hWndNewParent); public GUI() { // Initialize form fieds InitializeComponent(); openProgram() } private void openProgram() { process.StartInfo.FileName = "-filepathhere-"; process.Start(); IntPtr ptr = IntPtr.Zero; while ((ptr = process.MainWindowHandle) == IntPtr.Zero) ; SetParent(process.MainWindowHandle, trackerPanel.Handle); MoveWindow(process.MainWindowHandle, 0, 0, this.Width - 90, this.Height, true); } 

 [DllImport("user32.dll", SetLastError = true)] static extern IntPtr SetParent(IntPtr hWndChild, IntPtr hWndNewParent); private void button2_Click(object sender, EventArgs e) { var process = new Process(); process.StartInfo.FileName = "notepad.exe"; process.Start(); SetParent(process.MainWindowHandle, panel1.Handle); } 

 SetParent(process.MainWindowHandle, IntPtr.Zero);