c/c++语言开发共享如何解析用逗号分隔的字符串？

从cplusplus strtok示例修改：

 #include  #include  int main () { char str[] ="1,2,3,4,5"; char *pt; pt = strtok (str,","); while (pt != NULL) { int a = atoi(pt); printf("%dn", a); pt = strtok (NULL, ","); } return 0; } 

我不知道上面评论中提到的function，但是按照你要求的方式做你想做的事我会尝试这个或类似的东西。

 char *strings = "1,5,95,255"; char number; int i = 0; int value = 1; printf ("value%d = ", value); value++; while (strings[i] != NULL) { number = string[i]; i++; if (number == ',') printf("nvalue%d = ",value++); else printf("%s",&number); } 

如果你没有可修改的字符串，我会使用strchr 。 搜索下一个,然后像那样扫描

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 #define MAX_LENGTH_OF_NUMBER 9 char *string = "1,5,95,255"; char *comma; char *position; // number has 9 digits plus  char number[MAX_LENGTH_OF_NUMBER + 1]; comma = strchr (string, ','); position = string; while (comma) { int i = 0; while (position < comma && i <= MAX_LENGTH_OF_NUMBER) { number[i] = *position; i++; position++; } // Add a NULL to the end of the string number[i] = ''; printf("Value is %dn", atoi (number)); // Position is now the comma, skip it past position++; comma = strchr (position, ','); } // Now there's no more commas in the string so the final value is simply the rest of the string printf("Value is %dn", atoi (position)l