#include <iostream> using namespace std; struct node { int val; struct node *left, *right; }; node *rotateleft(node *root) {//左旋 可以记下来 余下都可反推 node *t = root->right; root->right = t->left; t->left = root; return t; } node *rotateright(node *root) {//右旋 node *t = root->left; root->left = t->right; t->right = root; return t; } node *rotateleftright(node *root) {//先左子树左旋在整体右旋 root->left = rotateleft(root->left); return rotateright(root); } node *rotaterightleft(node *root) {//先右子树右旋在整体左旋 root->right = rotateright(root->right); return rotateleft(root); } int getheight(node *root) {//获取二叉树高度,用于判断时候需要平衡调整 if(root == null) return 0; return max(getheight(root->left), getheight(root->right)) + 1; } node *insert(node *root, int val) {//此为二叉排序树的插入算法加入平衡调整 if(root == null) { root = new node(); root->val = val; root->left = root->right = null; } else if(val < root->val) { root->left = insert(root->left, val); if(getheight(root->left) - getheight(root->right) == 2)//左右子树不平衡时 root = val < root->left->val ? rotateright(root) : rotateleftright(root); } else { root->right = insert(root->right, val); if(getheight(root->left) - getheight(root->right) == -2) root = val > root->right->val ? rotateleft(root) : rotaterightleft(root); } return root; } int main() { int n, val; scanf("%d", &n); node *root = null; for(int i = 0; i < n; i++) { scanf("%d", &val); root = insert(root, val); } printf("%d", root->val); return 0; }
本文来自网络收集,不代表计算机技术网立场,如涉及侵权请联系管理员删除。
ctvol管理联系方式QQ:251552304
本文章地址:https://www.ctvol.com/c-cdevelopment/606668.html