c/c++语言开发共享C++实现四则运算器(带括号)

本文实例为大家分享了c++实现四则运算器的具体代码,供大家参考,具体内容如下基本分析可以看另一篇文章:c++实现四则运算器(无括号)栈的实现//stack.h#ifndef stack_h#defin

c/c++开发分享C++实现四则运算器(带括号)实例为大家分享了c++实现四则运算器的具体代码,供大家参考,具体内容如下

基本分析可以看另一篇文章:c++实现四则运算器(无括号)

栈的实现

  //stack.h  #ifndef stack_h  #define stack_h  #include<iostream>  class stack_int  {  private:   int* bottom;   //栈底   int* top;    //栈顶   unsigned int capacity;//栈容量   unsigned int size; //栈大小  public:   stack_int() :bottom(new int[11]), top(bottom), capacity(10), size(0) {};   stack_int(unsigned int capacity) :bottom(new int[capacity+1]),top(bottom), capacity(capacity),size(0){};   int operator[](unsigned int i) const   {   return *(bottom + i);   }   bool isempty()const { return bottom == top; }   bool isfull()const { return size == capacity-1; }   unsigned int getsize()const { return size; }   unsigned int getcapacity()const { return capacity; }   int gettop()const   {   if (!isempty())   return *(top - 1);   else   return -1;   }   void settop(int i)   {   if (!isempty())   {   *(top - 1) = i;   }   }   void push(int i)   {   if ((top - bottom)<capacity)   {   *top = i;   top++;   size++;   }   else   {   std::cout << "stack full!" << std::endl;   stack_expansion();   push(i);   }   }   int pop(int &val)   {//返回值为1则栈未空,返回值为0则栈已空无法出栈   if (top > bottom)   {   top--;   size--;   val = *top;   return 1;   }   else   {   std::cout << "stack empty!" << std::endl;   return null;   }   }  private:   void stack_expansion()   {//栈扩容   std::cout << "正在扩容中..." << std::endl;   int newcapacity = 2 * capacity + 1;   int* newbottom = new int[newcapacity + 1];   int* newtop = newbottom;   for (int i = 0; i < size; ++i)   {   *newtop = *bottom;   newtop++;   bottom++;   }   bottom = newbottom;   top = newtop;   capacity = newcapacity;   }  };    #endif

主程序

  //main.c  #include"stack.h"  #include<iostream>  using namespace std;  bool is_digit(char i)  {//是数字   if (i == '1' || i == '2' || i == '3' || i == '4' || i == '5' || i == '6' || i == '7' || i == '8' || i == '9' || i == '0')   return true;   else return false;  }  bool is_operator(char i)  {//是运算符   if (i == '+' || i == '-' || i == '*' || i == '/' || i == '(' || i == ')'||i=='=')   return true;   else return false;  }  bool get_priority(char pre,char cur)  {//获取两个符号间的优先级,pre为靠前的字符,cur为靠后的字符   if ((pre == '+' || pre == '-') && (cur == '*' || cur == '/'))   return false;   else if (pre == '(' || cur == '(')   return false;   else   return true;  }  int do_operation(int lnum, char ope, int rnum)  {   if (ope == '+')   return lnum + rnum;   if (ope == '-')   return lnum - rnum;   if (ope == '*')   return lnum * rnum;   if (ope == '/')   return lnum / rnum;  }  /*  1+2*3=  1*(2+1*(3+5)+4*3)=  先乘除,后加减,有括号先算括号内的  1+5*4-345+36/6*4+145*4*5-52=  */    void do_arithmetic()  {   stack_int s;   stack_int num_stack;//数据栈   stack_int ope_stack;//符号栈   char current_char;   current_char = getchar();   bool overflag = false;//结束标志   bool errorflag = false;//出错标志   while (overflag != true)   {//未遇到=号时不断进行四则运算   if (is_digit(current_char))   {//遇到数字符号则将完整的数解析出来并保存于栈中   int num = 0;   num = current_char - '0';//符号转数字   current_char = getchar();//获取下一个字符   while (is_digit(current_char))   {   num = num * 10 + (current_char - '0');   current_char = getchar();   }   num_stack.push(num);   //cout <<"the number is " <<num << endl;   }   if (current_char == ' '||current_char=='n')   {//空格或换行则继续   current_char = getchar();   continue;   }   if (is_operator(current_char))   {//遇到运算符则将运算符保存于运算符栈中   int ope = '?';   //如果当前符号栈非空,则不断根据优先级决定是否进行一次运算   while ((!ope_stack.isempty()) && (get_priority((char)ope_stack.gettop(), current_char)))   {//如果前一个运算符优先级更高   ope_stack.pop(ope);   //cout << "找到了前一个运算符为: " << (char)ope << endl;   int lnum, rnum;   //符号栈非空时,数据栈应该至少有两个数,否则出错   if (num_stack.isempty())   {    cout << "error: 数据栈缺失两个元素,解析失败!" << endl;    errorflag = true;    overflag = true;    break;   }   num_stack.pop(rnum);   if (num_stack.isempty())   {    cout << "error: 数据栈缺失一个元素,解析失败!" << endl;    errorflag = true;    overflag = true;    break;   }   num_stack.pop(lnum);   lnum = do_operation(lnum, (char)ope, rnum);//进行运算   num_stack.push(lnum);   }   if (current_char == '=')   {//如果解析到=号了,解析完成   if (!ope_stack.isempty())   {    errorflag = true;    cout << "error: 缺失)" << endl;   }   overflag = true;   break;   }   ope_stack.push(current_char);   if (current_char == ')')   {//右括号则出栈两次,将右括号和匹配的左括号出栈   ope_stack.pop(ope);   if (ope_stack.isempty())   {    cout << "error: 没有与)相匹配的(" << endl;    errorflag = true;    overflag = true;    break;   }   ope_stack.pop(ope);   }   current_char = getchar();   }   }   //for (int i = 0; i < num_stack.getsize(); ++i)   // cout << num_stack[i] << "t";   //cout << endl;   //for (int i = 0; i < ope_stack.getsize(); ++i)   // cout << (char)ope_stack[i] << "t";   if (!errorflag)   cout << num_stack.gettop() << endl;  }    int main()  {   cout << " ______________" << endl;   cout << "|整数四则运算器|" << endl;   cout << " --------------" << endl;   cout << "功能介绍:进行整数表达式的四则运算" << endl;   cout << "可以使用的运算符:+ - * /" << endl;   cout << "使用方式:输入以=结尾的算数运算表达式,回车后即可得到运算结果" << endl;   cout << endl;   //2432+5423-534*42=   while (true)   {   cout << "____________________" << endl;   cout << "--------------------" << endl;   cout << "> ";   do_arithmetic();   }   return 0;  }

程序大部分与不带括号版本很相似,主要更改了两个方面:

1.对于左括号,令左括号左边运算符优先级低于左括号,右边运算符优先级高于左括号(即,只要含有左括号的比较结果均为无法进行运算,函数get_priority返回值永远为false)。

2.对于右括号,令右括号左边的运算符(除左括号外)优先级均高于右括号,并且当右括号左边的符号为左括号时,两个括号相抵消,左括号退栈。

遇到右括号时,两括号内的+ – * /运算全部可以进行,直到符号栈栈顶为左括号。

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