c/c++语言开发共享C语言实现三子棋源代码

  #pragma once  #include <stdio.h>  #include <stdlib.h>  #include <time.h>  #define row 3  #define col 3    //函数声明  void initboard(char board[row][col], int row, int col);  void displayboard(char board[row][col], int row, int col);  player(char board[row][col], int row, int col);  computer(char board[row][col], int row, int col);  char judge(char board[row][col], int row, int col);

  #include "game.h"  void initboard(char board[row][col], int row, int col)  {   int i = 0;   int j = 0;   for (i = 0; i < row; i++)   for (j = 0; j < col; j++)   board[i][j] = ' ';  }  //棋盘  // x | x | x   //---|---|---  // x | x | x   //---|---|---  // x | x | x   void displayboard(char board[row][col], int row, int col)  {   int i = 0;   int j = 0;   for (i = 0; i < row; i++)   {   //打印一行数据   for (j = 0; j < col; j++)   {   printf(" %c ", board[i][j]);   if (j < col - 1)   printf("|");   }   printf("n");   //打印分隔行   if(i<row-1)   for (j = 0; j < col; j++)   {   printf("---");   if (j < col - 1)    printf("|");   }   printf("n");   }  }   player(char board[row][col], int row, int col)  {   while (1)   {   int x = 0;   int y = 0;   printf("请输入你的棋子坐标（如第一行第一列为1 1）：n");   scanf("%d%d", &x, &y);   if (x <= row && x >= 1 && y <= col && y >= 1)   {   if (board[x - 1][y - 1] == ' ')   {   board[x - 1][y - 1] = '*';   break;   }   else   {   printf("该处已有棋子，请重新输入n");   continue;   }   }   else   printf("坐标范围错误,请重新输入");   }  }   computer(char board[row][col], int row, int col)   {   int x = 0;   int y = 0;   while (1)   {   x = rand() % row;   y = rand() % col;   if (board[x][y] == ' ')   {   board[x][y] = '#';   break;   }   }   }   int isfull(char board[row][col], int row, int col)//返回1表示棋盘已满，0表示棋盘没满   {   int i, j;   for (i = 0; i < row; i++)   {   for (j = 0; j < col; j++)   if (board[i][j] == ' ')    return 0;   }    return 1;   }     char judge(char board[row][col], int row,int col)   {   int i = 0;   //行有三个相连的情况   for (i = 0; i < row; i++)   {   if (board[i][0] == board[i][1] && board[i][1]==   board[i][2] && board[i][0] != ' ')   return board[i][0];   }   //列有三个相连的情况   for (i = 0; i < col; i++)   {   if (board[0][i] == board[1][i] && board[1][i]==   board[2][i] && board[0][i] != ' ')   return board[0][i];   }   //对角线三个相连的情况   if (board[0][0] == board[1][1]&& board[1][1]==board[2][2]&&board[0][0]!=' '   || board[0][2] == board[1][1]&&board[1][1] == board[2][0]&&board[0][2] != ' ')   return board[1][1];   //平局的情况（棋盘满了）   if (isfull( board , row,col) ==1)   {   return 'e';   }   return 'c';   }

  #include "game.h"    void menu()  {   printf("***************************n");   printf("***1.开始游戏 0.退出游戏***n");   printf("***************************n");   printf("请输入数字1或0:");  }  void game()  {   char r;   char board[row][col] = { 0 };   //初始化棋盘（清空棋盘）   initboard(board, row, col);   //打印棋盘   displayboard(board, row, col);   //人机对弈   while (1)   {   player(board, row, col);   displayboard(board, row, col);   r = judge(board, row, col);   if (r != 'c')   break;   computer(board, row, col);   displayboard(board, row, col);   r = judge(board, row, col);   if (r != 'c')   break;   }   //判断输赢   if (r == '*')   {   printf("玩家赢n");   }   else if (r == '#')   {   printf("电脑赢n");   }   else if (r == 'e')   {   printf("平局n");   }  }  int main()  {   srand((unsigned int)time(null));   int input = 0;   do   {   menu();   scanf("%d", &input);   switch (input)   {   case 1:   printf("开始游戏n");   game();   break;   case 0:   printf("退出游戏n");   break;   default:   printf("请输入正确的选项n");   break;   }   } while (input);   printf("游戏结束！");   return 0;  }