c/c++语言开发共享用于将EBCDIC printables原位转换为ASCII的C代码

从这里使用表格，从我的头顶：

 static const unsigned char e2a[256] = { 0, 1, 2, 3,156, 9,134,127,151,141,142, 11, 12, 13, 14, 15, 16, 17, 18, 19,157,133, 8,135, 24, 25,146,143, 28, 29, 30, 31, 128,129,130,131,132, 10, 23, 27,136,137,138,139,140, 5, 6, 7, 144,145, 22,147,148,149,150, 4,152,153,154,155, 20, 21,158, 26, 32,160,161,162,163,164,165,166,167,168, 91, 46, 60, 40, 43, 33, 38,169,170,171,172,173,174,175,176,177, 93, 36, 42, 41, 59, 94, 45, 47,178,179,180,181,182,183,184,185,124, 44, 37, 95, 62, 63, 186,187,188,189,190,191,192,193,194, 96, 58, 35, 64, 39, 61, 34, 195, 97, 98, 99,100,101,102,103,104,105,196,197,198,199,200,201, 202,106,107,108,109,110,111,112,113,114,203,204,205,206,207,208, 209,126,115,116,117,118,119,120,121,122,210,211,212,213,214,215, 216,217,218,219,220,221,222,223,224,225,226,227,228,229,230,231, 123, 65, 66, 67, 68, 69, 70, 71, 72, 73,232,233,234,235,236,237, 125, 74, 75, 76, 77, 78, 79, 80, 81, 82,238,239,240,241,242,243, 92,159, 83, 84, 85, 86, 87, 88, 89, 90,244,245,246,247,248,249, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57,250,251,252,253,254,255 }; void ebcdicToAscii (unsigned char *s) { while (*s) { *s = e2a[(int) (*s)]; s++; } } 

根据您的具体要求，我建议如下：

 #include  void inSituEbcdicToAscii (char *s) { static char etoa[] = " " " " " .<(+|& !$*); " // first char here is real space "-/ ,%_>? `:#@'="" " abcdefghi jklmnopqr " " stuvwxyz " " ABCDEFGHI JKLMNOPQR " " STUVWXYZ 0123456789 "; while (*s != '') { *s = etoa[(unsigned char)*s]; s++; } } int main (void) { char str[] = "xc8x85x93x93x96x40xa3x88x85x99x85x5a"; inSituEbcdicToAscii (str); printf ("%sn", str); return 0; } 

哪个输出Hello there! 来自等效的EBCDIC字符。 超出您感兴趣的所有其他字符都会转换为空格，但您可以将其更改为其他字符（请确保不要修改EBCDIC代码0x40 ，这是真实空间）。

你可能想要一个翻译表。 这是一个256个元素的一维数组; 每个位于其EBCDIC位置，其值是相同字符的ASCII值。

 const char ebcdicToAsciiTable[256]; 

然后，就地转换：

 void ebcdicToAscii(char *s) { size_t len = strlen(s); for (size_t i = 0; i < len; i++) s[i] = ebcdicToAsciiTable[(unsigned char)(s[i])]; } 

该表的内容留给读者练习。 ;）

最简单的是使用256条目查找表。 这是使用Python生成这样一个表的一种方法：

 print 'static const char kEbcdicToAscii[256] = {'; for i in range(256): print ' %d,' % ord(chr(i).decode('cp500')) print '};' 

然后解码：

 void ebcdicToAscii(char *s) { while(*s) *s++ = kEbcdicToAscii[(unsigned char)*s]; } 

这也可能是最快的方法，因为256字节的表很容易适合你的L1缓存。 如果你真的想将其他字符转换为'.' 而不是正确地转换它们，然后像​​这样修改表：

 import string print 'static const char kEbcdicToAscii[256] = {'; for i in range(256): asc = chr(i).decode('cp500') if asc not in string.ascii_letters + string.digits + ' <=>()+-*/&|!$#@.,;%_?"': asc = '.' print ' %d,' % ord(asc) print '};'