C语言实现矩阵翻转(上下翻转、左右翻转)分享

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C语言实现矩阵翻转 上下翻转与左右翻转

实例代码：

  #include <stdio.h>       void matrix (int m, int n, int t)   {     int arr[m][n];     int i, j, k;         for (i = 0; i < m; i++){       for (j = 0; j < n; j++){         scanf("%d", &arr[i][j]);       }     }     if (t == 0){//左右翻转         for (i = 0; i < m; i++){           for (j = n-1; j >= 0; j--){             if ( j == 0 ) {               printf("%d", arr[i][j]);             }             else {               printf("%d ", arr[i][j]);             }           }           printf("n");         }     }     else if (t == 1){//上下翻转       for (i = m-1; i >= 0; i--){         for (j = 0; j < n; j++){           if ( j == n - 1 ) {             printf("%d", arr[i][j]);           }           else {             printf("%d ", arr[i][j]);           }         }         printf("n");       }     }   }       int main()   {     int m, n, t;         scanf("%d %d %d", &m, &n, &t);     matrix (m, n, t);         return 0;   }     

 动态分配内存

  void matrix (int m, int n, int t)   {     int i, j;     int **arr=(int**)malloc(m*sizeof(int*));     for(i = 0; i < m; i++)     {       arr[i] = (int*)malloc(n * sizeof(int));       for(j = 0; j < n;j++)       {         scanf("%d", &arr[i][j]);       }     }     /*     int **arr = new int*[m];     for(i=0;i<m;i++)     {       arr[i] = new int[n];       for(j=0;j<n;j++)       {         scanf("%d", &arr[i][j]);       }     }     */     if (t == 0){//左右翻转         for (i = 0; i < m; i++){           for (j = n-1; j >= 0; j--){             if ( j == 0 ) {               printf("%d", arr[i][j]);             }             else {               printf("%d ", arr[i][j]);             }           }           printf("n");         }     }     else if (t == 1){//上下翻转       for (i = m-1; i >= 0; i--){         for (j = 0; j < n; j++){           if ( j == n - 1 ) {             printf("%d", arr[i][j]);           }           else {             printf("%d ", arr[i][j]);           }         }         printf("n");       }     }   }   

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